Wrong number of prints ? Not sure what I am doing wrong here.

Question

Hello,

I am not sure what I am doing wrong here. I followed all that was asked but then it gets to the final part and says "Bummer wrong number of prints" when it asks me to print 2 times in the directions.

even.py

import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
while start == False:
    num = random.randint(1, 99)
    if even_odd(num) == True:
        print("{} is even".format(num))
    else: 
        print("{} is odd".format(num))
    start -= 1

Answer 1 · 2016-07-04T06:18:23Z

July 4, 2016 6:18am

Hi Joseph your code looks great everywhere except for a small hiccup on line 7 where the while statement is. Since you have:

start = 5
while start == False:
    #body of while loop
    start -=1

The while loop never actually starts (which means 0 prints which explains the error) because start is not equal to false it is equal to 5 which is denoted in boolean as a true value. So alternatively you can get rid of the '== False' part all together and have it look like this:

start = 5
while start:
    #body of while loop
    start -=1

This means that as long as the start variable is pointing to a non-zero value(anything thats not nothing) the while loop will run. And since you decrement the value of start after each iteration it will eventually reach 0 and will break out of the loop. Great job though Joseph! and Happy Coding :) -CodyTheCoder

Answer 2 · 2016-07-04T15:08:23Z

July 4, 2016 3:08pm

Thanks so much for pointing that out !

Welcome to the Treehouse Community

Looking to learn something new?

Joeseph Wolfe

Joeseph Wolfe

Wrong number of prints ? Not sure what I am doing wrong here.

2 Answers

Cody Te Awa

Cody Te Awa

Joeseph Wolfe

Joeseph Wolfe