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Python Python Basics (2015) Letter Game App Even or Odd Loop

Spencer Hill
Spencer Hill
1,397 Points

Wrong number of prints but I have 2 as requested by task?

Wrong number of prints but I have 2 as requested by task?

even.py
import random

start = 5

while start == True:
    number = random.randint(1, 99)
    if even_odd(number) == 0:
        print ("{} is even".format(number))
    else:
        print ("{} is odd".format(number))
    start -= 1

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5

while start: 
    number = random.randint(1, 99)
    if even_odd(number):
        print ("{} is even".format(number))
    else:
        print ("{} is odd".format(number))
    start -= 1

your while loop was off.. start is never == True as it is assigned above equal to 5. it is only not True if start == 0. In addition, you must define your function before you call it.