Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialMona Jalal
4,302 Pointswrong number of prints
can someone give me a hint how to fix this? import random def even_odd(num): while (start): rand_num=random.randint(1,99) if rand_num%2 ==1 : print("{} is odd".format(rand_num)) start -=1
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
start = 5
import random
def even_odd(num):
while (start):
rand_num=random.randint(1,99)
if rand_num%2 ==1 :
print("{} is odd".format(rand_num))
start -=1
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
start = 5
3 Answers
jcorum
71,830 PointsMona, the while loop needs to be outside the even_odd() function, and called in that function. Something along these lines:
import random
start = 5
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
while start:
num = random.randint(1, 99)
if even_odd(num):
print("{} is even".format(num))
else:
print("{} is odd".format(num))
start -= 1
Good luck!
Mona Jalal
4,302 Pointsjcorum so it doesn't pass the following challenge: https://teamtreehouse.com/library/python-basics/letter-game-app/even-or-odd-loop it just says try again :( with no description of error!
jcorum
71,830 PointsVery sorry about that. I've edited it so it is now correct!
Levis Vazquez
961 PointsLevis Vazquez
961 PointsThank you.