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Python Python Basics (2015) Letter Game App Even or Odd Loop

Moses Lagoon
PLUS
Moses Lagoon
Courses Plus Student 660 Points
Posted by Moses Lagoon
Moses Lagoon
Courses Plus Student 660 Points

Wrong no. of prints error. However, logically it makes sense to me. I need help

import random start = 5 def even_odd(num): # If % 2 is 0, the number is even. # Since 0 is falsey, we have to invert it with not. return not num % 2 while start != 0: rnum = random.randint(1,99) if even_odd(rnum): print("{} is even".format(rnum)) else: print("{} is odd".format(rnum))

    start = start -1
even.py 
import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
    while start != 0: 
        rnum = random.randint(1,99)
        if even_odd(rnum):
            print("{} is even".format(rnum))
        else: 
            print("{} is odd".format(rnum))

        start = start -1

2 Answers

Wairton Rebouças
Wairton Rebouças
8,225 Points
Wairton Rebouças
Wairton Rebouças
8,225 Points

Hi, your problem is wrong indentation, instead of

import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
    while start != 0: 
        rnum = random.randint(1,99)
        if even_odd(rnum):
            print("{} is even".format(rnum))
        else: 
            print("{} is odd".format(rnum))

        start = start -1

you should do:

import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start != 0: 
    rnum = random.randint(1,99)
    if even_odd(rnum):
        print("{} is even".format(rnum))
    else: 
        print("{} is odd".format(rnum))
    start = start -1

The while must be outside of the function