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Start your free trialJericoe States
3,262 PointsWorking with logical operators
var results: [Int] = []
for n in 1...100 {
if n % 1 == 0 && n % 7 == 0 {
results.append(n)
}
}
/* If the number is both an odd number and a multiple of 7, append the value to the results array provided.
having troubles as to why my code is not working. I also can't remember what --> % means or stands for?*/
var results: [Int] = []
for n in 1...100 {
if n % 1 == 0 && n % 7 == 0 {
results.append(n)
}
}
2 Answers
lvwdhydynw
6,443 PointsHi Jericoe!
First: it's not something you have to do, but I recommend using brackets () so it's easy to find out what's going on in code.
Second: % is - if I remember it correctly - called reminder. It gets the value after diving. For example: if you divide 15 by 3, the reminder is 0, because there's nothing left, as you can get number 3 into number 15 5 times. Same for 16/4, 100/20 etc. However, try 10/3. How many times will number 3 get into 10? 3 times - and 3 times 3 is 9. However, we were diving 10. And what do you have to add to 9 to get number 10? Exactly, number 1 so reminder is 1. A few more examples: 15%7 = 1 (7 gets twice into 15 - 7*2 = 14 and what do you need to get 15? 1) 29%5 = 4 (5 gets 5 times into 25 - 5*5 = 25 and what do you need to get 29? 4) 27%8 = 3 (27-8*3 = 27-24 = 3)
And now about the code: it almost works. First, you have to know what are even numbers (2,4,6,8,...) and odd numbers (3,5,7,...). You are working with odd numbers here but to achieve that, you have to work with even numbers first :) So, how to find out what's even number? What's typical for even numbers? Yes, you can divide them by 2 (=you can divide them with 2 and the value of reminder is 0). Write this and then you just have to make the opposite using the "!" (!=). At this moment, it should be okay :)
Jericoe States
3,262 Points//1// var results: [Int] = []
//2// for n in 1...100 {
//3// if n % 1 == 0 && n % 7 == 0 {
//4// results.append(n) } }
2*// This line of codes lets us insert a loop using integers ranging from 1 to 100, easy.
3*// (if n % 1 == 0) if I replace %1 with %2 or %0, wouldn't that make them even numbers,,, integers?
3*// Where exactly would you put the (!=) --> ( if (!)n % (!)1 == 0 && (!)n % (!*)7 == 0)
lvwdhydynw
6,443 Pointsn%2==0 -> even numbers !(n%2==0) -> odd numbers
You may even add "!" right to equals (n%2!=0), however this caused a problem as Xcode misinterpreted and therefore it didn't work the way it should