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Python Python Basics (2015) Shopping List App Continue

Posted by Abdillah Hasny
Abdillah Hasny
Courses Plus Student 3,886 Points

why this code isn't work

this code work properly as the question command

def loopy(items):
  for x in range(len(items)):
    if items[0] == "a":
      continue
    else:
      print(items[x])
Luke Mason
Luke Mason
1,596 Points
Luke Mason
Luke Mason
1,596 Points

There's not one right way to do it, but here's how I did mine:

''' python <p> def loopy(items): for item in items: if 'a' in item: continue else: print(item) </p> '''
What this does is takes a list as a parameter for the function "loopy". Then sets a temporary iterator named item. Each value in the list "items" will be assigned one at a time to the iterator "item". Then in the if statement each "item" will be checked to see if it contains the value 'a'. If it does, the loop continues. If it does not contain 'a' then we print out the value of the item.

I'm no python expert, so you're code looks like it'd work to me. But you're calling methods that are a bit overboard. You don't need to check values in a range or even pass the length of the list of items.

the "for x in items" would iterate through the list items until the end by default. No need to spell it out further in the code. :-) And your final print statement is too specific in the wrong way. You don't need the "x" index of list "items". You just need to print "x". X is not an index value, it is temporarily holding a list item from the list "items".

Abdillah Hasny
Abdillah Hasny
Courses Plus Student 3,886 Points

if you make like 

def loopy(items): 
    for item in items: 
        if 'a' in item: 
            continue 
        else: 
            print(item)

when 'a' is not at index 0 the string still skipped, i just think to check just the index 0 because the question , but thanks for your answer

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,441 Points

Since you are using an index as your for loop variable you need to look up the individual item before looking at its index[0] element.

items[0] is the first element of the items list

items[0][0] is the first character of the first element of the items list

To correct your code, add the correct indexing:

def loopy(items):
  for x in range(len(items)):
    if items[x][0] == "a":  # <-- added [x]
      continue
    else:
      print(items[x])

A more direct solution would be to operate on the elements of items directly:

def loopy(items):
  for item in items:
    if item[0] == "a":
      continue
    else:
      print(item)

This can be simplified by inverting the if condition:

def loopy(items):
  for item in items:
    if item[0] 1= "a":  # print if NOT starts with 'a'
      print(item)