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Start your free trialDezhi Zhu
2,662 Pointswhy my code not work?
Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".
def loopy(items):
# Code goes here
for item in items:
if item[0] = "a":
continue
else:
print(item)
1 Answer
Stuart Wright
41,120 PointsThe logic is all correct, you just have a syntax error. You need to use == to test equality. A single = sign is an assignment operator and is not used to test equality.