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Start your free trialJabor Al thani
2,926 PointsWhy isn't the function going through ?
Ive replaced print with return and then thing still doesn't go through ?
func fizzBuzz(n: Int) -> String {
for n in 1...100 {
if ( n % 3 == 0 ) && ( n % 5 == 0 ) {
return("FizzBuzz")
} else if ( n % 3 == 0 ) {
return("Fizz")
} else if ( n % 5 == 0 ) {
return("Buzz")
} else {
return "\(n)"
}
}
2 Answers
Brandon Mahoney
iOS Development with Swift Techdegree Graduate 30,149 PointsYou don't need the for loop, you are just checking for n. Also the last else is unnecessary as well.
func fizzBuzz(n: Int) -> String {
if ( n % 3 == 0 ) && ( n % 5 == 0 ) {
return("FizzBuzz")
} else if ( n % 3 == 0 ) {
return("Fizz")
} else if ( n % 5 == 0 ) {
return("Buzz")
}
return "\(n)"
}
Jabor Al thani
2,926 PointsThanks for the help Brandon , it finally went through .