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Java Java Basics Getting Started with Java Strings and Variables

SHANTANU RANA
PLUS
SHANTANU RANA
Courses Plus Student 524 Points
Posted by SHANTANU RANA
SHANTANU RANA
Courses Plus Student 524 Points

Why is variable to be written after we use %s ?

String firstName = "Shaun";

console.printf("Hello my name is %s\n"firstName)

2 Answers

Grigorij Schleifer
Grigorij Schleifer
10,365 Points
Grigorij Schleifer
Grigorij Schleifer
10,365 Points

Hi SHANTANU,

the %s is a String formatter. It will be replaced by the variable (here your name). After you close the text ("some text with the %s formatter" there should be a comma and then the variable name. It is a convention of the printf method. This method takes a text first and then the variable name that replaces the %s String formatter.

Makes sense?

And I see two typos here:

console.printf("Hello my name is %s\n", firstName); // comma and semicolon added

Grigorij

S Nafees Hyder
S Nafees Hyder
649 Points
S Nafees Hyder
S Nafees Hyder
649 Points

because %s may refer to format specifiers for variable interpolation in C standard and other libraries