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Start your free trialTall Toad
2,746 PointsWhy is console.log() not having an issue showing numbers without the parseInt?
// Collect input from a user
const choosenNumber = prompt("Whats your favourite number?");
// Convert the input to a number const favouriteNumber = (choosenNumber);// I know parseInt should be present before the (chosenNumber). But when I run this workspace on the browser, I'm not getting any errors or Nan.
// Use Math.random() and the user's number to generate a random number
const randomNumber = Math.floor( Math.random() * choosenNumber) + 1;
// Create a message displaying the random number
console.log(${randomNumber} is a number between 1 and ${favouriteNumber}.
);
1 Answer
Steven Parker
231,184 PointsFor some operations, JavaScript can tell that a number is needed and it performs type coercion, which is essentially converting the string into a number for you automatically.
But you don't want to rely on this, since there will be other cases where it can't perform this for you. Here's an example where it won't work:
const choosenNumber = prompt("Whats your favourite number?");
const twice = choosenNumber + choosenNumber;
console.log(`${choosenNumber} added to itself is not ${twice}, is it?`);
Tall Toad
2,746 PointsTall Toad
2,746 PointsThanks for the reply Steven Parker, I'm new to coding. Some parts make sense some don't or eventually do. As a newbie, How does one evaluate if they are doing well or not?
Steven Parker
231,184 PointsSteven Parker
231,184 PointsIf you generally complete the quizzes and challenges with only occasionally needing to review a lesson, you're doing quite well indeed!