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Start your free trialSteven Wheeler
2,330 PointsWhy does "println" not work but "printf" does in "Exceptions" lesson?
Hey there!
Out of interest why does "printf" work here (3rd line): "catch (IllegalArgumentException iae) { System.out.println("Woah there!"); System.out.printf("There was an error: %s", iae.getMessage()); }"
but if we were to use "println" it goes crazy?
Thanks! :)
3 Answers
Craig Dennis
Treehouse Teacherprintf
is for printing formatted text and takes additional parameters. println
is for printing lines of text and does not do substitution.
Make sense?
Mario Blokland
19,750 PointsHi Steven Wheeler,
System.out.println("")
can only print an unformatted string. Thus, if you would leave the %s out of the String everything would work as expected.
System.out.printf("") // The f in printf stands for formatted
this version can print regular strings and formatted strings e.g. %s, %d and so on. If you put %s in the string you are using the formatted version and replace the placeholder %s with some string.
I hope that cleared things up a little bit for you.
Mario Blokland
19,750 PointsOh, just saw that Craig was faster than me and already answered your question :-)
Steven Wheeler
2,330 PointsExcellent, makes sense! Thanks guys!