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723 PointsWhy does my color stay the same throughout the loop ?
let html = '';
let red = Math.floor(Math.random() * 256);
let green = Math.floor(Math.random() * 256);
let blue = Math.floor(Math.random() * 256);
let randomRGB = rgb( ${red}, ${green}, ${blue})
;
console.log(red) console.log(green) console.log(blue)
for(let i = 0; i <= 10; i++){
html += <div style="background-color: ${randomRGB}">${i}</div>
;
}
document.querySelector('main').innerHTML = html;
How will I refactor this code so that I get a random RGB for each loop ?
1 Answer
Joseph Yhu
PHP Development Techdegree Graduate 48,637 PointsIt's because the code that generates random colors is outside the for loop, which means it will generate only a single random color. You have to put the code inside, like this:
for (let i = 0; i <= 10; i++) {
red = Math.floor(Math.random() * 256);
green = Math.floor(Math.random() * 256);
blue = Math.floor(Math.random() * 256);
randomRGB = `rgb( ${red}, ${green}, ${blue} )`;
html += `<div style="background-color: ${randomRGB}">${i}</div>`;
}