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Java Java Basics Perfecting the Prototype Parsing Integers

Why do you need to convert a String into an int if you enter an int? int answer=Integer.parsel(answerToLife);

Why do you need to convert a String into an int if you enter an int? int answer=Integer.parsel(answerToLife);

Also, does java recogonise "answer" as separate as long as its lower case and connects them?

ParsingInts.java
String answerToLife = "42";
int answer= Integer.parseInt(answerToLife);

3 Answers

"42" is of type String. Though it has a number in it, it is still a String data type. In order for the "answer" variable to hold the number 42, you must use Integer.parseInt(answerToLife); This will make "answer" equal to the int parsed from "answerToLife".

So 42 is an integer but because its being typed in its a String?

because if its an integer why does it need to be a String? I'm sorry, I'm just lost.

So a string is a sequence of characters, the compilers doesn't necessarily care if it has numbers or letters in it. "H3llo" would still be a string. Think of it like characters being strung across the screen. So the answerToLife object is 42, but that's a string. If you were to try to combine answerToLife twice, it would not equal 84, because they are a sequence of characters, and not ints.

I would read the documentation a little

https://docs.oracle.com/javase/7/docs/api/java/lang/String.html

And if you don't want to read that here is my very loosely based example!

``` int answerToLife = 42; answerToLife + answerToLife = 84

String answerToLife = 42; answerToLife + answerToLife = "42 42" ```

int is always mathematical. String is said and literal? Thank you very much. I was so pissed.