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Start your free trialRicardo Sala
16,212 PointsWhy casting inside a class method?
Why when implementing the compareTo method, the first thing that Craig does is casting to Treet?
We are creating a method inside the Treet class, is it supposed to be a Treet already? If it wasn't, the method applied would be that of Object instead of the one of Treet, right?
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Need some help here to fully understand the relationships there!
THANK YOU!
1 Answer
Lars Reimann
11,816 PointsWe are casting the parameter obj
to Treet
, not this
. this
is already of type Treet
, but obj
has the type Object
, as declared in the method signature. This is necessary, because we implement the interface Comparable
, which expects a method int compareTo(Object)
. So in order to access any stuff of a Treet
instance, we first need to tell Java that this object we pass in is indeed an instance of this class. Nothing prevents us, however, from passing in a Date or an Array. In this case the casting would fail and we would get a runtime exception.
So it's better to implement the generic interface Comparable<T>
. The T
here is a variable for a type. If we implement this interface, we need to have a method int compareTo(T)
--- notice the type of the parameter we pass in. In our case, we want to compare instances of Treet
only to other instances of Treet
, so we implement Comparable<Treet>
and add a method int compareTo(Treet)
. Now the compiler can check that we only make valid comparisons and we no longer get any exceptions at runtime from invalid type casts.