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Python Python Basics (2015) Number Game App Squared

Posted by Lakshmi R
Lakshmi R
2,568 Points

While doing this challenge, int("2") doesn't give 2 as the output, when under a function call. What is wrong?

The code is attached. For an input of "2", the output is obtained as "2""2""2", instead of 4

squared.py 
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"

def squared(num):
    num = input("Enter a number: ")

    try:
        num1 = int(num)
        return(num1 * num1)
    except ValueError:
        return(num * len(num))

1 Answer

Michael Hulet
Michael Hulet
47,913 Points
Michael Hulet
Michael Hulet
47,913 Points

Your logic here is right, but you don't need to call input. You should instead just operate on the parameter that the function gives you