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Python Python Basics (2015) Letter Game App Even or Odd Loop

gurinder singh
PLUS
gurinder singh
Courses Plus Student 1,422 Points
Posted by gurinder singh
gurinder singh
Courses Plus Student 1,422 Points

where i have an error???

error??

even.py 
import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
while start = False:
    num = random.randint(1, 99)
    if num % 2 ==0:
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    start -= 1

1 Answer

Wade Williams
Wade Williams
24,476 Points
Wade Williams
Wade Williams
24,476 Points

Your while loop condition is actually assigning start to False instead of checking if start is equal (==) to False. Fixing that won't get you the right answer though.

You really want to run your while loop as long as the variable start is greater than 0. The instructions say run the while loop until start is "Falsey", which 0 is "Falsey" and numbers greater than 0 are "Truthy".

The pythonic way to do this is:

# while start is Truthy or greater than 0
while start: