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2,951 PointsWhere exactly is the default "1" being passed onto?
in the code
public void drive(int lapsleft) { lapsDriven+=lapsLeft; barCount-=lapsLeft; } public void drive() {drive(1);}
What parameter is the 1 taking by default? lapsLeft? lapsDriven?
1 Answer
andren
28,558 PointsThe line drive(1)
is just calling the drive(int lapsleft)
with 1 as an argument. Which means that it ends up being passed to the lapsleft
parameter.
Arguments (values passed into a function) is automcaitcally assigned to parameters based on position. So the first argument goes to the first parameter. Since 1 is the first argument and lapsleft
is the first parameter 1 gets assigned to lapsleft
.