when im trying to write the last part at this video the program give me the error "invalid literal for int with base 10"

Hey! I had tne same issue so I started to google it and try to change my code. The thing I realised that an error occures when we want a charcter to be an integer. But it's not true and we have no ecxeption for it (I dont't know why as it's ValueError).

And after a long time i found the solution:

try:
        number_tickets = int(number_tickets) 
        if number_tickets > tickets_remaining:
            raise ValueError
    except ValueError as err: 
        print("Try again. We have only {} tickets.".format(tickets_remaining))

As you can see I have no .format(err) . I think there's a problem with it. Btw if you have an error in different place yu can copy your code so we can see what's wrong.

I am getting the same issue:

 try:    

        howmuch = int(howmuch)
        if howmuch > tickets_remaining:
            raise ValueError("Sorry, the maximum amount you can have is {}".format(tickets_remaining))
    except ValueError as err:

        print("Sory we have ran into an error, {}, please try again".format(err))

The problem is when it tries to convert it into an int. Before we added the "raise" and it was just "except ValueError" it would have caught it and produced your warning. e.g

try:
    number_tickets = int(number_tickets) 
except ValueError:
    print("hey thats not a number")

That would work