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Python Python Basics (2015) Letter Game App Exiting

Posted by Sid K
Sid K
Courses Plus Student 206 Points

what's wrong with this code ??

This is correctly working in python IDLE but it is shown an error here in workspace

firedoor.py 
import sys
inp = input("enter a letter to play the game..")
if inp == 'n' or "N":
    print("Enjoy the show!")
else:
    sys.exit()

2 Answers

Hwi Han
Hwi Han
5,008 Points
Hwi Han
Hwi Han
5,008 Points

Try this. It says other than 'n'

import sys inp = input("enter a letter to play the game..") if inp.lower () != 'n': print("Enjoy the show!") else: sys.exit()

Kenneth Love
STAFF
Kenneth Love
Treehouse Guest Teacher
Kenneth Love
Kenneth Love
Treehouse Guest Teacher

ors don't work in Python like they do in English. You read that code as "if the input value is 'n' or 'N", then do something". But Python sees "if the input value is 'n', or if 'N' is truthy, then do something".

You'll want something like if inp == 'n' or inp == 'N':. Each side of the or is evaluated on its own.