Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Atul Varma
4,285 PointsWhat's wrong with the code ?
Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".
def loopy(items):
for item in items:
if item.index[0] == "a":
continue
else:
print(item)
2 Answers
Julian Gutierrez
19,201 PointsVery close, you don't need ".index" on your if conditional.
if item[0] == "a":
leonardbode
Courses Plus Student 4,011 PointsAtul, looking at your code:
def loopy(items):
for item in items:
# item is a list, to find first index of a list, do item[0]
if item.index[0] == "a":
continue
else:
print(item)
If you have any other questions I will update my answer, if you do not have any other questions:
Remember to upvote and to choose the best answer so that your question receives a checkmark in forums.
Kind regards,
Leo