Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Java Java Basics Perfecting the Prototype Looping until the value passes

Posted by Sami Manzur
Sami Manzur
527 Points

What's wrong with my line of code?

I'm not sure what's wrong with my line of code here. Treehouse keeps telling me that I need to have the string formatted with the response with the console.printf function but I thought that's what I'm already doing?

Any help would be greatly appreciated!

console.printf("Because you said <response>, you passed the test! \n\n");

3 Answers

Philip Gales
Philip Gales
15,193 Points
Philip Gales
Philip Gales
15,193 Points 
console.printf("Because you said , you passed the test! \n\n");

////////////It wants you to use %s to return the variable "response"//////////////////

console.printf("Because you said %s, you passed the test!", response);
Arnav Singh
Arnav Singh
636 Points
Arnav Singh
Arnav Singh
636 Points

String answerSay=console.readLine("What is 1+1? "); console.printf("because you said %s,you passed",answerSay");

/Here i have made a separate variable called answerSay, %s is the name of the variable and after coma we put the condition in which it was/

Arnav Singh
Arnav Singh
636 Points
Arnav Singh
Arnav Singh
636 Points

^ after ';' the code will be in the next line.