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Python Python Basics (2015) Number Game App Squared

Posted by KOMBO NASSORO
KOMBO NASSORO
Courses Plus Student 126 Points

What's wrong with my code as it works only on workspace but it doesn't work on challenge task python(Number Game App)

This challenge is similar to an earlier one. Remember, though, I want you to practice! You'll probably want to use try and except on this one. You might have to not use the else block, though. Write a function named squared that takes a single argument. If the argument can be converted into an integer, convert it and return the square of the number (num ** 2 or num * num). If the argument cannot be turned into an integer (maybe it's a string of non-numbers?), return the argument multiplied by its length. Look in the file for examples.

squared.py 
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"

def squared():
    try:
        num=input("Enter a number: ")
    except ValueError:
        print("That's not a number")

        if num==int:
            return(num ** 2)
        else:
            return(num*len(num))
squared()

1 Answer

Krishna Pratap Chouhan
Krishna Pratap Chouhan
15,203 Points
Krishna Pratap Chouhan
Krishna Pratap Chouhan
15,203 Points

Firstly, it takes an argument, forget input() in any challenge here on treehouse.

And maybe you meant something like...

def squared(arg):
    try:
        return arg **2;
    except:
        return len(arg)*arg

But that's not the answer either.

As for your code, its never going to enter except statement. Try should do something that makes it throw an exception, in which case it goes to except.

You cannot do "var==num" to check if its a number. Use type() instead. In which case you dont need to worry about try and except...

If its int, reutrn arg to the power of 2, else return len(arg)*arg.

Answer is...

# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"

#Firstly, it takes an argument, forget input()
def squared(arg):
    try:
        return int(arg) **2;
    except:
        return len(arg)*arg