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Python Regular Expressions in Python Introduction to Regular Expressions Escapes

Posted by Evan Mnatsekanov
Evan Mnatsekanov
1,785 Points

whats wrong here

escapes.py 
import re
def first_number(number):
    return(re.search(r'\d', number))

def numbers(fivenumbers):
    return(re.search(r'/d' * 5, fivenumbers))

2 Answers

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

The instructions for task 2 say to write a function "that takes two arguments: a count as an integer and a string", but this code takes only one argument and forces the count to always be 5.

Also, the escape character is a backslash, so the regex for a digit would be "\d" (as you used in task 1) instead of "/d".

Javi Caballero
Javi Caballero
7,422 Points
Javi Caballero
Javi Caballero
7,422 Points

I copied and pasted your code into the challenge and it worked just fine for me, maybe try entering it in again?

Evan Mnatsekanov
Evan Mnatsekanov
1,785 Points

it says "numbers() takes 1 positional argument but 2 were given"