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Start your free trialErik Luo
3,810 PointsWhat's wrong?
I think I'm very close. Why is the FizzBuzz logic incorrect?
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
if n % 3 == 0 {
return "Fizz"
}
if n % 5 == 0 {
return "Buzz"
}
else (n % 3 == 0 && n % 5 == 0) {
return "FizzBuzz"
}
// End code
return "\(n)"
}
1 Answer
Chase Marchione
155,055 PointsHi Erik,
Since you're specifying logic for your else, I'll use else if instead of else.
I would write the clause with the multiple conditions first. The reason for this is that any 'n' that divides without a remainder into both 3 and 5 will, therefore, also print something for the if statement that only checks for 3, and the one that only checks for 5. Since we're looking for "Fizz", "Buzz", or "FizzBuzz", and not "FizzFizzBuzz" or "BuzzFizzBuzz":
if (n % 3 == 0 && n % 5 == 0) {
return "FizzBuzz"
}
else if (n % 3 == 0) {
return "Fizz"
}
else if (n % 5 == 0) {
return "Buzz"
}
Hope this helps!
Erik Luo
3,810 PointsErik Luo
3,810 PointsThank you.