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Python Python Basics (2015) Shopping List App Break

Leen Leenaerts
PLUS
Leen Leenaerts
Courses Plus Student 2,367 Points

what's wrong?

?

breaks.py
def loopy(items):
for item in items
  if item == "STOP":
    break
  print(item)

2 Answers

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

You are missing a colon and an else statement. Remember every block start must have a colon. Let me show you:

def loopy(items):
    for item in items:
      if item == "STOP":
        break
      else:
        print(item)
Leen Leenaerts
PLUS
Leen Leenaerts
Courses Plus Student 2,367 Points

got it thanks

why do i need the else? can't I put the print-statement outside the if so it will run anyway if not "STOP" since then we break?

Jennifer Nordell
seal-mask
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

I believe that in a real life scenario that should work. However, I tried it and it doesn't pass the challenge :( They clearly want an else even if it isn't strictly needed.