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Python Python Basics (2015) Letter Game App Even or Odd Loop

What's worng in this code?

What's wrong in this code?

I'll appreciate your help

even.py
import random

start = 5

def main():
    while start:
        random_num = random.randint(1, 99)
        if even_odd(random_num) == True:
            print("{} is even".format(random_num))
        else:
            print("{} is odd".format(random_num))
        start -=


def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

1 Answer

Brian Jensen
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree seal-36
Brian Jensen
Treehouse Staff

Check out this solution from Himal Shakya view solution

I have pasted it here with python syntax enabled:

import random
start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start:
  num = random.randint(1, 99)
  if even_odd(num):
    print("{} is even".format(num))
  else:
    print("{} is odd".format(num))
  start = start - 1