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Java Java Basics Perfecting the Prototype String Equality

Posted by mvl
mvl
2,618 Points

What is wrong with this code?

For some reason the compiler gives me a error but when I excute this code in workspaces everything is okay.

// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample.equalsIgnoreCase(secondExample)) {
  console.printf("first is equal to second");'

JavaTester.java:123: error: illegal start of expression
  private static void pass() {
  ^
JavaTester.java:123: error: illegal start of expression
  private static void pass() {
          ^
JavaTester.java:123: error: ';' expected
  private static void pass() {
                ^
JavaTester.java:123: error: ';' expected
  private static void pass() {
                            ^
JavaTester.java:127: error: illegal start of expression
  private static void fail(String hint) {
  ^
JavaTester.java:127: error: illegal start of expression
  private static void fail(String hint) {
          ^
JavaTester.java:127: error: ';' expected
  private static void fail(String hint) {
                ^
JavaTester.java:127: error: ')' expected
  private static void fail(String hint) {
                                 ^
JavaTester.java:127: error: illegal start of expression
  private static void fail(String hint) {
                                      ^
JavaTester.java:127: error: ';' expected
  private static void fail(String hint) {
                                       ^
10 errors

1 Answer

Unsubscribed User
Unsubscribed User
1,321 Points
Unsubscribed User
Unsubscribed User
1,321 Points

I would check your brackets. Also posting your full code would really help so we can see what you are looking at.