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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Muhammad Dar
Muhammad Dar
1,175 Points

what is wrong with my code. Please help

I can't seem to figure out where I went wrong as the hints are not suggestive of main issue

even.py 
    import random
    start=5
    def even_odd(num):
        if num%2==0:

            print ("{} is even".format(num))
        else:
            print("{} is odd."format(num)

        # If % 2 is 0, the number is even.
        # Since 0 is falsey, we have to invert it with not.
    while start!=0:
                  randomnum=random.randint(1,99)
                  even_odd(randomnum)
                  start-=1
luke begley
luke begley
1,120 Points
luke begley
luke begley
1,120 Points

I do not know python but your else: print("{} is odd."format(num) should be print("{} is odd".format(num)) if it were to match the format of the if statement.

1 Answer

Wade Williams
Wade Williams
24,476 Points
Wade Williams
Wade Williams
24,476 Points

It appears you have syntax error when printing out your odd number. The "." is in the wrong place and you're missing a closing parenthesis. Also check all of your indentation, it's hard to tell with your code sample, but looks like the you might have some indentation errors.

print("{} is odd."format(num)

# Should be

print("{} is odd".format(num))

A note about your while loop condition, the pythonic way is to do:

# start is Truthy as long as it's greater than 0
# 0 is Falsey so loop will break when start == 0
while start:

Here's all the code refactored

import random

def even_odd(num):

    if num % 2 == 0:
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))

    return not num % 2

start = 5

while start:
    even_odd(random.randint(1, 99))
    start -= 1