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Python Python Basics (2015) Shopping List App Continue

Tariq Kfaery
Tariq Kfaery
956 Points
Posted by Tariq Kfaery
Tariq Kfaery
956 Points

what is wrong with my code here?

Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

breaks.py 
def loopy(items):
    # Code goes here
    x = []
    for x in items:
        x.append(items)
        if x.index(0) == "a":
            continue
        else:
            print x

3 Answers

Stuart Wright
Stuart Wright
41,120 Points
Stuart Wright
Stuart Wright
41,120 Points

Here are some hints to get you started:

  • The challenge doesn't ask you to create a new list and append items to it. You can delete both of these lines. You only need to check whether or not each item begins with 'a', and print it out if not.
  • The correct syntax for getting the first character of a string is x[0] (where x is the string).
  • The print function needs (), so correct syntax is print(x).
Krishna Pratap Chouhan
Krishna Pratap Chouhan
15,203 Points
Krishna Pratap Chouhan
Krishna Pratap Chouhan
15,203 Points

lets go through the code and question, with couple of things to remember:

string can be treated as a List. so in string="Abrakadabra", string[0]='A', string[1]='b'...so on.

def loopy(items):
    # Code goes here
    x = []
    #creating an empty list
    for x in items:
        #for each string in items
        x.append(items)
        #Appending whole list of items into the list x. Now x is list of list.
        if x.index(0) == "a":
            #checking if index of '0' in the list is a
            continue
        else:
            #trying to print x, which is an array.[treehouse uses python3.0 so print function is print().
            print x

Lets see what we need to do now:

def loopy(items):
    # Code goes here
    #Loop through each item in items 
    for item in items:
        #If the character at index 0 of the current item is the letter "a", continue
        if item[0] == 'a':
            continue;
        else:
            #else print the item
            print(item);

Hope this helps.