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iOS Functions in Swift Adding Power to Functions Function Parameters

Tyler Dotson
PLUS
Tyler Dotson
Courses Plus Student 1,740 Points

What is wrong here??

says set the result to a constant named result. did It appears that I have done this and I have also tested it on xcode but still does not seem to accept the code in treehouse.

functions.swift
// Enter your code below
func getRemainder(value a: Int, divisor b: Int) -> Int {
    let remainder = a % b

    return remainder
}

let result = getRemainder(a: 10, b: 3)

1 Answer

Jeff McDivitt
Jeff McDivitt
23,970 Points

Hi Tyler - You do not need to include what you have in the body of your function

func getRemainder(value a: Int, divisor b: Int) -> Int {
    return a % b
}

let result = getRemainder(value: 10, divisor: 3)