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Start your free trialMohammed Alotaibi
Courses Plus Student 1,493 Pointswhat is wrong
what is mistake?
var results: [Int] = []
for n in 1...100 {
print("\(n * 2 - 1)")
results = [n]
}
results
1 Answer
Mitchell Richmond
5,401 PointsYou need to write an if statement that determines if the number is odd AND a multiple of 7. You can do this by first finding out if the number divided by 2 has a remainder, if it has a remainder it is an odd number. Then you can find out if the number divided by 7 has a remainder, if it does not have a remainder then it is a multiple of 7. Here is how I did it:
var results: [Int] = []
for n in 1...100 { // Enter your code below if (n % 2 != 0) && (n % 7 == 0) {
results.append(n)
}
// End code
}
So I said, if the remainder is NOT 0 when divided by 2 and if the remainder IS 0 when divided by 7, append the number.
wwyattw
10,389 Pointswwyattw
10,389 PointsThe question is asking you to append number to results IF they are both odd and multiple of 7.
You need to find a logic to get those numbers by using %. If a number % 2 == 1, that's an odd number. And a number % 7 == 0, that number is multiple of 7. By using && to combine both logics together in an IF statement. You should pass the code.
for n in 1...100 { if n % 2 == 1 && n % 7 == 0 { results.append(n) } }