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Start your free trialnader adam
Courses Plus Student 548 Pointswhat is the wrong here
func fizzBuzz(n: Int) -> String { // Enter your code between the two comment markers for x in 1...100{ if (x % 3 == 0) && (x % 5 == 0){ print("FizzBuzz") } else if (x % 3 == 0){ print("Fizz") } else if (x % 5 == 0){ print("Buzz") } else { print(x) } } // End code return "(n)" }
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
for x in 1...100{
if (x % 3 == 0) && (x % 5 == 0){
print("FizzBuzz")
} else if (x % 3 == 0){
print("Fizz")
}
else if (x % 5 == 0){
print("Buzz")
}
else {
print(x)
}
}
// End code
return "\(n)"
}
2 Answers
Dane Parchment
Treehouse Moderator 11,077 PointsOk well for starters, I advise you re-read the directions, you are supposed to return the string values, not print them. Also for some reason you are looping through the values 100 times. Remember we are not actually performing the full FizzBuzz challenge where you do the loop, instead you are seeing if the provided parameter value returns either fizz, buzz or fizzbuzz. Finally, your code will always return the number, even if it is divisible by either 3 or 5.
So let's get to work fixing this up:
For starters let's get rid of that loop:
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
if (x % 3 == 0) && (x % 5 == 0){
print("FizzBuzz")
} else if (x % 3 == 0){
print("Fizz")
}
else if (x % 5 == 0){
print("Buzz")
}
else {
print(x)
}
// End code
return "\(n)"
}
Now let's change those print statements to return statements:
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
if (x % 3 == 0) && (x % 5 == 0){
return "FizzBuzz"
} else if (x % 3 == 0){
return "Fizz"
}
else if (x % 5 == 0){
return "Buzz"
}
else {
return x
}
// End code
return "\(n)"
}
Now for the next part we need to remember what it is we are doing:
The program is going from an integer to a string: n:Int -> String, using the provided variable n, to convert. So with that in mind, lets get replace the x with n, more for staying with the provided parameters than anything else.
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
if (n % 3 == 0) && (n % 5 == 0){
return "FizzBuzz"
} else if (n % 3 == 0){
return "Fizz"
}
else if (n % 5 == 0){
return "Buzz"
}
else {
}
// End code
return "\(n)"
}
Finally let's place our final return statement in the proper location:
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
if (n % 3 == 0) && (n % 5 == 0){
return "FizzBuzz"
} else if (n % 3 == 0){
return "Fizz"
}
else if (n % 5 == 0){
return "Buzz"
}
else {
// End code
return "\(n)"
}
}
And that's it we are done, if you have any questions or concerns please let me know.
nader adam
Courses Plus Student 548 Pointswow
thanks a lot