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Start your free trialWan Nor Adzahari Wan Tajuddin
2,438 PointsWhat is regular expression \s+ ?
In the Splitting Strings video, Craig used \w
to take out all the words comprising of letter A to Z from a string. So why is it that in this code challenge we are using \s
instead?
package com.example;
import java.util.Date;
public class BlogPost {
private String mAuthor;
private String mTitle;
private String mBody;
private String mCategory;
private Date mCreationDate;
public BlogPost(String author, String title, String body, String category, Date creationDate) {
mAuthor = author;
mTitle = title;
mBody = body;
mCategory = category;
mCreationDate = creationDate;
}
public String getAuthor() {
return mAuthor;
}
public String getTitle() {
return mTitle;
}
public String getBody() {
return mBody;
}
public String getCategory() {
return mCategory;
}
public Date getCreationDate() {
return mCreationDate;
}
public String[] getWords() {
return mBody.split("[^\\s]+");
}
}
1 Answer
Rebekah Smith
7,263 PointsHere's an excerpt from the challenge description:
"Since we don't need to worry about special characters, let's just use the regular expression pattern \s+ (or any one or more white space character)"
\s indicates a white space. So [^\s] is any non-white space and includes letters, numbers, special characters
\w indicates a word character, equivalent to [a-zA-Z_0-9]. Special characters don't match.