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Java

Julian Rios
Julian Rios
3,458 Points
Posted by Julian Rios
Julian Rios
3,458 Points

What is !isDunked set to in the while loop expression at the beginning? Is it still false like in the initialization?

I am just confused on if the isDunked variable changes to true when the ! operand is added to the beginning of the variable. or if it is just a way of reading variables as false.

1 Answer

james south
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james south
Front End Web Development Techdegree Graduate 33,271 Points
james south
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points

the ! is negating whatever it is put in front of, so if the variable is initialized as false, !false is true, which will allow the while loop to enter and run, and it will run until something changes the variable to true, at which point !true would be false, and the while loop would exit

Julian Rios
Julian Rios
3,458 Points
Julian Rios
Julian Rios
3,458 Points

What I am not seeing is this. Wouldn't !isDunked && ballsThrown <=3 both need to be false in order to run the code block below? 

while (!isDunked && ballsThrown <= 3) {
      console.printf("Try #%d ...%n", ballsThrown + 1);
      isDunked = skill.nextBoolean();
      ballsThrown++;
    }