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Start your free trialJade Thomason
1,917 Pointswhat is happening?
what is happening that this won't work?
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
for n in 1...100 {
if (n % 3 == 0) && (n % 5 == 0) {
print("FizzBuzz")
} else if (n % 3 == 0) {
print("Fizz")
} else if (n % 5 == 0) {
print("Buzz")
} else {
print(n)
}
}
// End code
return "\(n)"
}
2 Answers
Jason Anders
Treehouse Moderator 145,860 PointsHi Jade,
All challenges are very specific when in comes to instructions being followed. This one in particular is extremely specific and must be followed to the letter.
With that said, in addition to the print
statements not being what the instructions ask for (as stated by Simon), there are a few other things not being followed:
- The instructions say to not create a range of values, which you have with the
for loop
- The instructions state not to include a default case, but you have an
else
clause
Other than that, the syntax is fine ... just go back and give the instructions a careful read and make the necessary changes to satisfy exactly what the challenge is needing.
Keep Coding! :)
Simon Di Giovanni
8,429 PointsPart of challenge asks you to change your 'print' statements to 'return' statements.
Try changing them to see if the challenge accepts it.
Simon Di Giovanni
8,429 PointsSimon Di Giovanni
8,429 PointsI didn’t even notice the other points of that challenge! Thanks for a much more detailed answer!