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Java Java Basics Perfecting the Prototype String Equality

Posted by Svetlana Ponomareva
Svetlana Ponomareva
699 Points

What is a compiler problem here: if (firstExample equalsIgnoreCase(thirdExample)) {...}

or if (firstExample equalsIgnoreCase("hello")) {...}

Equality.java 
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
if (firstExample == secondExample){
console.printf("first is equal to second");
}
String thirdExample = "HELLO";
if (firstExample equalsIgnoreCase(thirdExample)) {
console.printf ("firsd and third are the same ignoring case");
  System.exit(0);
}

1 Answer

tobiaskrause
tobiaskrause
9,160 Points
tobiaskrause
tobiaskrause
9,160 Points 
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
if (firstExample.equals(secondExample)){
console.printf("first is equal to second");
}

String thirdExample = "HELLO";
if (firstExample.equalsIgnoreCase(thirdExample)) {
console.printf ("firsd and third are the same ignoring case");
}

Don't use "==" to compare strings in Java. We do this in other languages but this wont work in Java. == checks if references of Objects are equal, while .equals checks the content of the string.