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Java Java Basics Perfecting the Prototype String Equality

what am i missing?

it says try again..is this a valid code?

Equality.java
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if ( firstExample.equals("hello")) { 
  if (secondExample.equals("hello")) {
    console.printf("first is equal to second ");
    System.exit(0);
  }
}

2 Answers

Daniel Babbev
Daniel Babbev
10,354 Points

You have to use the variable's name as an argument in equals() and equalsIgnoreCase() methods. The correct code looks like:

// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";

if(firstExample.equals(secondExample)){
   console.printf("first is equal to second");
}

if(firstExample.equalsIgnoreCase(thirdExample)){
    console.printf("first and third are the same ignoring case");
}
console.printf("first is equal to second ");

this code right here bud, you used printf even though you dont use any variable with your set of strings. I mean like this. (Sorry, as English isn't my native language. Can't explain very good.)

console.printf("My name is %s", name);

you can use println or just print if you just wanted to print set of words/strings, like this

console.println("first is equal to second");

or

console.print("first is equal to second");