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Aven Morgan
217 PointsWhat am I forgetting?
I am unsure what I am doing wrong
String firstName = "Aven";
console printf("firstName can code in Java!");
// I have setup a java.io.Console object for you named console
2 Answers
Nejc Vukovic
Full Stack JavaScript Techdegree Graduate 51,574 PointsHi Aven.
String firstName = "Aven";
console.printf("%s can code in Java!", firstName);
When you call any kind of a method on any kind of an object you denote the method call with a "."
Like in my code above: console"."printf -> this denotes that you are calling the printf method (which prints to the screen) on the console object.
This line ("%s can code in Java!", firstName); uses the Java string formatting -> a way you format/input variables into a string.
Hope this helped.
Happy Coding!!!
Dyrhoi .
3,173 PointsYour question in unclear, but judging from your code I reckon you want to print the string firstName
Now you can't in Java print out a variable that is inside quotes.
To get around this problem you need to use something called concatenation, which adds an element to another element. In this case, string to string.
In Java you do this by adding a simple plus sign.
Example:
String fish = 'Gold Fish';
printf(fish + " is a cute fish");
More advanced way is using the String.format built in Java.
Example:
String fish = 'Gold Fish';
printf("I love %s", fish);