Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialJohn User
613 Pointswhat am i doing wrong?
String firstName="John"; console.printf("firstName");
// I have setup a java.io.Console object for you named console
String firstName="John";
console.printf("String")
2 Answers
Lucas Santos
19,315 PointsJust looking at your code I see you are missing a semicolon and with in your printf it should be printing firstName.
What you have:
String firstName="John";
console.printf("String")
what it should be:
String firstName = "John";
console.printf("%s can code in Java!");
%s holds the string variable value.
Kathryn Ann
10,071 PointsTo add to Lucas's answer, you'll also need to include the variable within the parentheses to tell it what to replace the placeholder (%s) in the string with, like this:
("%s can code in Java!", firstName);
John User
613 PointsJohn User
613 PointsThanks guys!