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Java Java Basics Perfecting the Prototype Censoring Words - Using String Equality

Fabiyan Adell
Fabiyan Adell
365 Points

viable input code?

In the video, craig put those curly brackets { after if (noun.equalsIgnoreCase("dork")) with } ending System.exit(0); My output worked just fine without those curly brackets. Do I still need to put those in the code and why did mine still work without them? Thanks in advance

import java.io.Console;

public class TreeStory {

public static void main(String[] args) {
    Console console = System.console();
    /*  Some terms:
        noun - Person, place or thing
        verb - An action
        adjective - A description used to modify or describe a noun
        Enter your amazing code here!
    */
 // __Name__ is a __adjective__ __noun__. They are always__adverb __ __verb.
  String ageAsString = console.readLine("How old are you?  ");
  int age = Integer.parseInt(ageAsString);
  if (age < 13) {
    //Insert exit code
    console.printf("Sorry you must be at least 13 to use this program. \n");
    System.exit(0);
  }

String name = console.readLine("Enter a name: "); String adjective = console.readLine("Enter an adjective: "); String noun = console.readLine("Enter an noun: "); if (noun.equalsIgnoreCase("dork")) console.printf("That langauge is not allowed. Exiting. \n\n"); System.exit(0); String adverb = console.readLine("Enter an adverb: "); String verb = console.readLine("Enter an verb: ");

console.printf("Your TreeStory:\n-------------------\n"); console.printf("%s is a %s %s. ", name, adjective, noun); console.printf("They are always %s %s. \n", adverb, verb);

1 Answer

Steven Parker
Steven Parker
231,184 Points

There should be a difference in performance. Without the braces, the "if" would only apply to the printf statement after it, which would cause the program to always exit at that point — even when you enter a different word.