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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Variables: What's wrong with this?

console.printf("%s, can write Java", firstName);

Name.java
// I have setup a java.io.Console object for you named console
String firstName = "George";
console.printf("%s, can code in Java\n", firstName);

2 Answers

Well, you are printing an extraneous ',' after "firstName" and '\n' at the end of the message. Also, you are missing '!' at the end of the message you are printing.

Stick to the instructions of the challenge presented as it is machine that's evaluating your code / output, rather than human who can be considerate. Here's a solution:

String firstName = "Srikar";
console.printf("%s can code in Java!", firstName);
Matthew Hardy
Matthew Hardy
4,063 Points

Deleting the first comma in your second line of code, the one located after the %s, worked for me