Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Java Java Basics Getting Started with Java IO

alan alhamid
PLUS
alan alhamid
Courses Plus Student 114 Points
Posted by alan alhamid
alan alhamid
Courses Plus Student 114 Points

Using the console's printf method, display a message that says, "First name: ", followed by the first name that the user

Using the console's printf method, display a message that says, "First name: ", followed by the first name that the user has entered. it doesn't go the way it says

IO.java 
// I have imported java.io.Console for you.  It is a variable called console.
String firstName = console.readLine ("Alan");
String lastName = console.readLine ("Alhamid");
Console.printf("%s\n, %s");
Jonathan Hermansen
Jonathan Hermansen
25,935 Points

You got a typo: Console -> console. Also, you got to tell printf what the %s are.

1 Answer

Rick Gleitz
Rick Gleitz
47,840 Points
Rick Gleitz
Rick Gleitz
47,840 Points

Hi Alan, Jonathan is right, Console needs to be console and you need to pass the variable firstName after a comma to specify what the %s is. This is done by putting a comma after the string (but still inside the parens) and typing firstName. Also, you need to delete the comma and second %s inside the string, as well as putting First Name: at the beginning of the string.

Hope this helps!