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Start your free trialZach Freitag
20,341 PointsUsing reduce method, flatten the customerNames array of arrays.
Using reduce method, flatten the customerNames array of arrays. In other words, take all the names from each array inside customerNames and place them in one big array. Store the flattened array in the flattenedCustomerNames variable. You can use the array in the comments below for reference.
const customerNames = [
[ "John", "Sandy", "Tyrone", "Elizabeth", "Penny" ],
[ "Barry", "Wanda", "Jamal", "Hayden" ],
[ "Portia", "Pam", "Philip" ]
];
let flattenedCustomerNames;
// flattenedCustomerNames should be: ["John", "Sandy", "Tyrone", "Elizabeth", "Penny", "Barry", "Wanda", "Jamal", "Hayden", "Portia", "Pam", "Philip"]
// Write your code below
4 Answers
Zach Freitag
20,341 PointsThis worked!
flattenedCustomerNames = customerNames.reduce((arr, innerNames) => [ ...arr, ...innerNames], []);
console.log(flattenedCustomerNames);
Cheers!
Dan Otieno
23,495 PointsThis on the console: const customerNames = [ [ "John", "Sandy", "Tyrone", "Elizabeth", "Penny" ], [ "Barry", "Wanda", "Jamal", "Hayden" ], [ "Portia", "Pam", "Philip" ] ]; let flattenedCustomerNames; flattenedCustomerNames = customerNames.reduce((arr, innerNames) => [ ...arr, ...innerNames], []); (12) ["John", "Sandy", "Tyrone", "Elizabeth", "Penny", "Barry", "Wanda", "Jamal", "Hayden", "Portia", "Pam", "Philip"]
Noah Yasskin
23,947 Pointswith syntax highlighting:
flattenedCustomerNames = customerNames.reduce((arr, innerNames) => [...arr, ...innerNames], []);
Theo Lufkin
Web Development Techdegree Graduate 15,577 PointsWhy does 'innerNames' work, and not come up as 'undefined' like when I try to use a different name. 'innerNames' is also not defined anywhere in the code.