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Start your free trialMark Cai
1,505 PointsUsing case statement does not work
What is the issue when using case statement for FizzBuzz?
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
switch true {
case n % 3 == 0: return "Fizz"
case n % 5 == 0: return "Buzz"
case n % 3 && n % 5 == 0: return "FizzBuzz"
// End code
default: return "\(n)"
}
}
1 Answer
Elliot Rutherfoord
7,684 PointsHey man, this logic is what worked for me on this one:
if (n % 3 == 0) && (n % 5 == 0) { return("FizzBuzz") } else if (n % 3 == 0) { return("Fizz") } else if (n % 5 == 0) { return("Buzz") }
put that in between the comments and it should work :)
Mark Cai
1,505 PointsMark Cai
1,505 PointsThank you. Yes, I know using the 'if' statements resolves the challenge. However, I wanted to get it working with 'case' statement.
Elliot Rutherfoord
7,684 PointsElliot Rutherfoord
7,684 PointsThe switch method entails more code and unreadability, so it's feasible that Pasan hasn't accepted this answer to encourage more elegant code. If you have a way that works, use it :)