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5,276 PointsUnable to print out every member of items
I used the index method but I can't determine what's wrong with my code.
def loopy(items):
# Code goes here
for item in items:
if item.index(0) = "a":
continue
elif print(item)
1 Answer
Chris Freeman
Treehouse Moderator 68,441 PointsOn a string, the index
method searches if the item is in the string. So index(0)
is searching for a number. This is not allowed as you can only search for string within another string.
Instead use the "slice" syntax. Also, the compare needs double-equal sign. And "elif" should be "else"
def loopy(items):
# Code goes here
for item in items:
if item[0] == "a":
continue
else:
print(item)