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Start your free trialLee Morgan
2,419 PointsTrouble with a custom constructor
I am basically just completely lost here as to what this code challenge wants me to do. I have put in as much as I can, but even that is probably wrong. The videos fly through everything and don't take time to explain anything that they are doing. What am I supposed to do here?
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
public class LandingActivity extends Activity {
public Button mThrustButton;
public TextView mTypeLabel;
public EditText mPassengersField;
public Spaceship mSpaceship;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_landing);
mThrustButton = (Button)findViewById(R.id.thrustButton);
mTypeLabel = (TextView)findViewById(R.id.typeTextView);
mPassengersField = (EditText)findViewById(R.id.passengersEditText);
Spaceship mSpaceship = new Spaceship();
mSpaceship =
}
}
public class Spaceship {
private String mType;
private int mNumPassengers = 0;
public String getType() {
return mType;
}
public void setType(String type) {
mType = type;
}
public int getNumPassengers() {
return mNumPassengers;
}
public void setNumPassengers(int numPassengers) {
mNumPassengers = numPassengers;
}
public Spaceship() {
mType = "SHUTTLE";
}
public Spaceship(String type) {
mType = type;
}
}
1 Answer
Steve Hunter
57,712 PointsHi Lee,
The Spaceship class has two possible constructors. One defines a Spaceship of type "SHUTTLE", the other takes a String to define its own type - that's the one you want to use here.
So, adding:
mSpaceship = new Spaceship("FIREFLY");
in the onCreate
method will use the second custom constructor that takes a string.
I hope that makes sense!
Steve.