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JavaScript JavaScript Array Iteration Methods Array Manipulation Practice reduce()

Hamzah Iqbal
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.a{fill-rule:evenodd;}techdegree
Hamzah Iqbal
Full Stack JavaScript Techdegree Student 11,145 Points

This reduce method should work, but why isn't it?

```const phoneNumbers = ["(503) 123-4567", "(646) 123-4567", "(503) 987-6543", "(503) 234-5678", "(212) 123-4567", "(416) 123-4567"]; let numberOf503;

numberOf503 = phoneNumbers.reduce((sum, phoneNumber) => {

if(phoneNumber.substring(2,4) === "503") {

return phoneNumbers +1;

} return phoneNumbers;

},0); // numberOf503 should be: 3 // Write your code below

console.log(numberOf503);

Right now it is returning the last in the array, but I can't see why.  The substring should return the specified digits.

```app.js
const phoneNumbers = ["(503) 123-4567", "(646) 123-4567", "(503) 987-6543", "(503) 234-5678", "(212) 123-4567", "(416) 123-4567"];
let numberOf503;


numberOf503 = phoneNumbers.reduce((sum, phoneNumber) => {

  if(phoneNumber.substring(2,4) === "503") {


    return phoneNumbers +1;


  }
return phoneNumbers;


},0);
// numberOf503 should be: 3
// Write your code below

console.log(numberOf503);

1 Answer

Steven Parker
Steven Parker
231,269 Points

It looks like there are two issues:

  • string indexes begin at zero, and the substring stop value should be the value after the last index
  • the function should return the total (sum) instead of the array itself (phoneNumbers)
numberOf503 = phoneNumbers.reduce((sum, phoneNumber) => {
  if (phoneNumber.substring(1,4) === "503") {
    return sum + 1;
  }
  return sum;
}, 0);