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Start your free trialJustus Aberson
1,035 PointsThis code is correct right?
Hey guys, I'm doing the FizzBuzz challenge and I really don't want to look to the solutation, so I hope one of you guys can explain me what I'm doing wrong, the bummers says: Double check your logic for FizzBuzz values and make sure you're returning the correct string! Thanks.
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
if (n % 3 == 0) {
return "Fizz"
}
if (n % 5 == 0) {
return "Buzz"
}
if (n % 3 == 0) && (n % 5 == 0) {
return "FizzBuzz"
}
// End code
return "\(n)"
}
2 Answers
Jason Anders
Treehouse Moderator 145,860 PointsHey Justus,
You've got the syntax right, it's just the order that the conditionals are checking the logic. Remember, that once a condition returns true, the compiler stops checking.
With that in mind, if a number is divisible by 3 (as your first condition is checking for), the compiler stops and will not check to see if it is also divisible by 5. So, you just need a little bit of a reorder of the conditionals to make sure the number can be checked for both 3 and 5.
Hope that helps to explain it for you. :)
Keep Coding!
Julien riera
14,665 PointsHello,
You're almost there!
You miss the order the code checks your conditions. Try this conditional instead:
if n % 3 == 0 && n % 5 == 0 {
print("FizzBuzz")
} else if n % 3 == 0 {
print("Fizz")
} else if n % 5 == 0 {
print("Buzz")
}
If you need more explanation, feel free to ask about it.
Otherwise, just let us know if that solves the issue you're having.
Cheers,
Julien