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Start your free trialconnor hoare
7,933 PointsThis code compiles in a playground but not on here. FizzBuzz.
When calling the function in a playground it prints the correct String
func fizzBuzz(n: Int) -> String {
if (n % 3 == 0) && (n % 5 == 0) {
print("FizzBuzz")
} else if n % 5 == 0 {
print("Fizz")
} else if n % 3 == 0 {
print("Buzz")
} else {
print("\(n)")
}
return "\(n)"
}
1 Answer
Jason Anders
Treehouse Moderator 145,860 PointsHi Connor,
Yes, your code is correct syntactically, but it isn't following the instructions set forth in the Challenge. All challenges on Treehouse have very specific instructions that must be followed exactly, but this challenge is even more specific and extremely picky.
You will need to go over the instructions line by line and refactor you code to match exactly what is asked for in order to have this challenge pass.
Keep Coding! :)