Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialKhoa Nguyen
1,781 PointsThe test case is always fail
Please check my code.
def loopy(items):
# Code goes here
for item in items:
if item == 'a' and items.index(item) == 0:
continue
else:
print(item)
2 Answers
Pete P
7,613 PointsBe careful. You're not looking for an item named 'a', you should instead be checking the '0' index (the first letter) of each item for the letter 'a'.
if first letter of the item == 'a', continue
else, print the item
Mohammed Alnemari
1,019 Pointsdef loopy(items):
for item in items:
if item[0]=="a":
continue
else:
print (item)